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Aug 30, 2013 at 15:24 vote accept Joel Wallman
Aug 29, 2013 at 19:47 answer added Carlo Beenakker timeline score: 1
Aug 29, 2013 at 18:55 history edited Joel Wallman CC BY-SA 3.0
Introduced a requirement that avoids the trivial counter-example B = C = 0
Aug 29, 2013 at 18:53 comment added Joel Wallman Thanks, I guess that is the obvious counterexample. I've edited the question to reflect some of the extra structure in my problem that avoids this.
Aug 29, 2013 at 18:50 comment added Carlo Beenakker no, just take as a counterexample $\Sigma_B=0=\Sigma_C$. Then $A+B=A$ and $C+D=D$, so your assumption fails unless $U_1=U_2$ and $V_1=V_2$.
Aug 29, 2013 at 16:47 review First posts
Aug 29, 2013 at 17:04
Aug 29, 2013 at 16:30 history asked Joel Wallman CC BY-SA 3.0