Timeline for Fixed component of an $S^1$ action on $S^n$
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 29, 2013 at 10:21 | comment | added | aglearner | this is very nice! Thank you very much! | |
| Aug 29, 2013 at 9:18 | vote | accept | aglearner | ||
| Aug 29, 2013 at 9:12 | vote | accept | aglearner | ||
| Aug 29, 2013 at 9:18 | |||||
| Aug 29, 2013 at 1:27 | history | edited | Allan Edmonds | CC BY-SA 3.0 |
Added more explanation.
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| Aug 29, 2013 at 1:02 | comment | added | Allan Edmonds | I'll edit the answer to provide a bit more detail on this point. It uses the h-cobordism theorem. | |
| Aug 28, 2013 at 21:31 | comment | added | aglearner | Allan, thanks again! So you say that $W\times D^2$ is a $(n+1)$-disk. As far as I understand you deduce this from the fact that $W$ is contractible. Could you tell me please what theorem one has to use here? (or maybe I miss again something simple) | |
| Aug 28, 2013 at 21:12 | comment | added | Allan Edmonds | Ah, the misprint started with saying $M$ was $(n-1)$-dimensional, instead of $(n-2)$-dimensional, and $W$ should be $(n-1)$ dimensional. I think I got it fixed, now. | |
| Aug 28, 2013 at 21:09 | history | edited | Allan Edmonds | CC BY-SA 3.0 |
edited body
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| Aug 28, 2013 at 20:20 | comment | added | aglearner | Allan thank you. I have a problem to understand your answer fully. It seems to me that there is a misprint in line 3: "$(n+1)$-disk $W\times D^2$"? | |
| Aug 28, 2013 at 20:06 | history | answered | Allan Edmonds | CC BY-SA 3.0 |