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Aug 28, 2013 at 15:08 comment added JDPoincare'S However, I think this space is too artifitial and it's better to work with signed Radon measures locally. So, Hahn decomposition theorem holds as you has pointed out
Aug 28, 2013 at 15:06 comment added JDPoincare'S Hahn decomposition theorem states that each signed measure is $\mu=\mu^+-\mu^-$ with $\mu^+,\mu^-$ mutually singular positive measures, one of them is finite. But the space of signed measures of my first comment was: $$\{\mu-\nu:\mu,\nu\mbox{ are positive measures}\}$$ (with formal sums). I was not asuming the Hahn decomposition property on it and it can't be deduced from definition because elements of this space aren't real measures (only formal expresions designed for working locally on compacts). If I want this property I have to asume it in the definition.
Aug 28, 2013 at 10:35 comment added R W No - $\mu_+$ and $\mu_-$ are not arbitrary! They are from the Hahn decomposition (be it in the space of general measures or in the space of densities of absolutely continuous measures, i.e., in $L^1$), so that they have to be mutually singular.
Aug 28, 2013 at 10:12 comment added JDPoincare'S Sorry for my typing mistakes. I wanted to write: $$\int f\cdot \varphi\,dx=\int \varphi\,d\mu^+-\int \varphi \,d\mu^-$$
Aug 28, 2013 at 10:06 comment added JDPoincare'S I say "problems" because $\mu^+,\mu^-$ seem to be too arbitrary. But perhaps there are not better descriptions. I'll go on reading. Thank you very much!
Aug 28, 2013 at 10:03 comment added JDPoincare'S I was afraid of changing the standard definition because I wanted to go on seeing this measures as distributions in the same way we see locally finite borel measures, but there is no problem. The only problem I have, if we use $\mathcal{M}^p$ for noting this subspace is to describe in an easy way the intersection $L^1_{loc}\cap \mathcal{M}^p$ (in the sense of distributions). Such functions $f$ verify: $$\int f\cdot\varphi \,dx=\int \phi \,d\mu^+ +\int \phi \,d\mu^-$$ for every $\varphi\in C^{\infty}_c$ and certain $\mu^+,\mu^-$ positive Radon measures
Aug 28, 2013 at 9:55 comment added R W Yes, precisely.
Aug 28, 2013 at 9:54 comment added JDPoincare'S I agree with you. I'm reading about related topic in other references just know and it seems that they only consider meausures locally (defined for bounded Borel sets). So, what you mean is that the space of signed Radon measures they are problably considerying is kind of the vector space of formal sums $\alpha\cdot \mu+\beta\cdot \mu$ with $\mu,\nu$ positive Radon measures, isn't it?
Aug 28, 2013 at 9:23 history answered R W CC BY-SA 3.0