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Aug 27, 2013 at 21:38 comment added fedja Yes to "effectively computable". The pdf link is in one of the last posts in the linked thread (the most recent version). As to better bounds and factors, I have to think a bit :).
Aug 27, 2013 at 16:46 comment added The Masked Avenger Can we say further that $n_0 \lt q$ and also from LTE one has $v_q(p^n - 1) \leq C(p,q) + v_q(n/n_0)$? Also, can one do better upper bounds with $C(p,q)$ than $C(p,q) \lt n_0 \log(p)/\log(q)$?
Aug 27, 2013 at 16:38 comment added The Masked Avenger Also, I would appreciate your take on my linked question on counting factors (see sidebar). Are there AoPS problems which take (something like) the approach suggested there?
Aug 27, 2013 at 16:31 comment added The Masked Avenger Thank you for looking at this. For sake of clarity, please confirm or deny the statement "C(p,q) is a value that depends only on p and q, and is just a uniformly effectively computable constant in p and q." (I've seen stuff where C returns a function and not a number.) Also, I am not finding a link to the PDF in the first post of your linked thread. Do you have a URL for the PDF?
Aug 27, 2013 at 13:56 history answered fedja CC BY-SA 3.0