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Oct 17, 2010 at 2:42 comment added Peter Shor I think the "standard formalism" is probably to deal with finite-dimensional Hilbert spaces and certain examples of infinite-dimensional Hilbert spaces, but not actually prove anything rigorous about infinite-dimensional Hilbert spaces in general.
Feb 5, 2010 at 14:13 comment added MBN I think it shouldn't be called algebraic because it is actually analytic. C* algebras are not part of algebra.
Feb 5, 2010 at 13:29 answer added Igor Khavkine timeline score: 5
Feb 4, 2010 at 8:35 answer added Orbicular timeline score: 2
Feb 3, 2010 at 22:56 comment added Yemon Choi OK, thanks, that helps. Not sure I can offer any useful answer, but at least I understand the question better now.
Feb 3, 2010 at 22:48 history edited Marcin Kotowski CC BY-SA 2.5
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Feb 3, 2010 at 21:52 history edited Steve Huntsman
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Feb 3, 2010 at 21:51 history edited Steve Huntsman
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Feb 3, 2010 at 21:39 answer added Steve Huntsman timeline score: 6
Feb 3, 2010 at 21:24 comment added Yemon Choi Could you please clarify, for those of us with limited physics background, what the "standard formalism" is and how it differs from "this algebraic stuff"? Are you talking about AQFT or something at lower levels?
Feb 3, 2010 at 21:16 history asked Marcin Kotowski CC BY-SA 2.5