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Aug 27, 2013 at 13:34 comment added Colin McLarty I do not see that Section 4 uses FLT. It looks like in this paper FLT is just a nice source of integer polynomials without rational solutions.
Aug 27, 2013 at 13:11 comment added Carlo Beenakker @Colin --- more general non-polynomial superpotentials are considered in section 4.
Aug 27, 2013 at 12:26 comment added Colin McLarty FLT comes into this via their specification of a specific superpotential $W$ which includes a term $\Phi_4[\Phi_1^p+\Phi_2^p+ (t\Phi_3)^p]$ (p.~3). Is there something in the theory that constrains them to that, or do they simply have the freedom to pick a superpotential that will relate to FLT this way?
Aug 27, 2013 at 9:36 history answered Carlo Beenakker CC BY-SA 3.0