Timeline for Algebraic Dual / Continuous Dual
Current License: CC BY-SA 2.5
2 events
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Feb 3, 2010 at 23:49 | comment | added | Ady | It is not hard to see that $\left|\ell_{2}\left(\gamma\right)\right|=\left|\gamma\right|$ in this case. OTOH, any mapping from $\gamma$ to $\mathbb{R}$ can be "extended'' to a linear (discontinuous) functional, so that $2^{\left|\gamma\right|}$ would be the dimension of the algebraic dual. | |
Feb 3, 2010 at 20:42 | history | answered | Ben | CC BY-SA 2.5 |