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Pavel Etingof
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  1. The Weierstrass function has two zeros per each parallelogram of periods, which may coincide, producing a double zero.

  2. This cover has degree 2. We need to quotient the elliptic curve $\Bbb C/\Lambda$ by the transformation $z\to -z$, which has order 2.

The branched cover (defined by the Weierstrass function) has degree 2. To obtain $\Bbb C\Bbb P^1$, we need to quotient the elliptic curve $\Bbb C/\Lambda$ by the transformation $z\to -z$, which has order 2.

  1. The Weierstrass function has two zeros per each parallelogram of periods, which may coincide, producing a double zero.

  2. This cover has degree 2. We need to quotient the elliptic curve $\Bbb C/\Lambda$ by the transformation $z\to -z$, which has order 2.

The branched cover (defined by the Weierstrass function) has degree 2. To obtain $\Bbb C\Bbb P^1$, we need to quotient the elliptic curve $\Bbb C/\Lambda$ by the transformation $z\to -z$, which has order 2.

Post Undeleted by Anton Geraschenko
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Pavel Etingof
  • 3.9k
  • 1
  • 28
  • 20

  1. The Weierstrass function has two zeros per each parallelogram of periods, which may coincide, producing a double zero.

  2. This cover has degree 2. We need to quotient the elliptic curve $\Bbb C/\Lambda$ by the transformation $z\to -z$, which has order 2.