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Apr 13, 2017 at 12:58 history edited CommunityBot
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Aug 24, 2013 at 0:54 comment added Eden Harder @WillSawin It is a cool idea! We can always to do this perturbation, but the nontransitivity is only related to the order of the numbers but not what they exactly are.
Aug 24, 2013 at 0:38 comment added Will Sawin What about the second question? There are many large nontransitive arrangements that are not nontransitive in an interesting way. For instance, take lots of small perturbations of your dice: $\{1.01,5.02,8.99\}$ and so on. This will give a large number of nontransitive dice for $m=3$. But this doesn't seem like the right case to consider.
Aug 23, 2013 at 23:45 comment added Eden Harder @WillSawin Yeah $n$ is the number of dice.
Aug 23, 2013 at 17:55 comment added Will Sawin What is $n$? The number of dice? How nontransitive must they be?
Aug 23, 2013 at 14:22 comment added Eden Harder $m=3$ for $n=3$, for example, the three dices are {1,5,9}, {2,6,7},{3,4,8}.
Aug 23, 2013 at 11:05 history asked Eden Harder CC BY-SA 3.0