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Aug 27, 2013 at 15:06 comment added J.Lodder Yes, there are two product structures on HH^*(k[G]; k[G]), one the Gerstenhaber product, the other the simplicial cup product. How these interact might lead to a new operad that acts on HH^* of a group ring. Of course, the cup-i products in the above paper lead to an E^{\infty} algebra for the simplicial cup product (not the Gerstenhaber product).
Aug 23, 2013 at 7:17 comment added Fernando Muro I've taken a look at your very interesting paper and noticed that your cup-$i$ products seem to be non-compatible with the usual cup-product in Hochschild homology.
S Aug 22, 2013 at 22:49 review Late answers
Aug 22, 2013 at 23:56
S Aug 22, 2013 at 22:49 review First posts
Aug 22, 2013 at 23:07
Aug 22, 2013 at 22:31 history answered J.Lodder CC BY-SA 3.0