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Oct 21, 2013 at 14:54 vote accept nikita
Sep 17, 2013 at 15:10 answer added Sam Nead timeline score: 10
Sep 17, 2013 at 14:45 comment added Sam Nead Kaavek - that product of twists works in the case of the closed surface. See below for a discussion of the surface with one boundary component.
Sep 1, 2013 at 21:55 comment added nikita Of course I meant up to isotopy.
Aug 23, 2013 at 4:35 comment added Andy Putman The Dehn twists fix the boundary pointwise, so unless you allow the boundary to move during your isotopies you cannot write the hyperelliptic involution as a product of Dehn twists. As for your expression, I have no idea what the $c_i$ are supposed to mean exactly.
Aug 22, 2013 at 15:47 comment added nikita Does it look something like this: $c_{2g+1}...c_1c_1....c_{2g+1}$?
Aug 22, 2013 at 14:13 comment added nikita I just meant that it has a boundary component, so involution acts on the boundary as well.
Aug 22, 2013 at 3:32 comment added Andy Putman Also in Farb-Margalit's book and Ivanov's survey.
Aug 22, 2013 at 3:19 comment added Igor Rivin Without boundary, I believe an expression can be found in Joan Birman's book.
Aug 22, 2013 at 3:12 comment added Andy Putman What exactly do you mean by the hyperelliptic involution on a surface with boundary? If you want it to be an involution, then it cannot fix the boundary pointwise (it has to rotate it by 180 degrees). What are your conventions on how mapping classes interact with the boundary?
Aug 22, 2013 at 2:27 history asked nikita CC BY-SA 3.0