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Oct 28, 2013 at 11:56 history edited Mohammad Golshani CC BY-SA 3.0
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Aug 22, 2013 at 2:47 comment added Andrés E. Caicedo @EverettPiper Another reason is that there is a very compelling picture of the universe as a (class) forcing extension of its $\mathsf{HOD}$, and the ultimate $L$ analysis would suggest the same ought to hold under appropriate assumptions replacing $\mathsf{HOD}$ with "ultimate $L$". But, in fact, since core-like models are ordinal definable, we expect that (ultimately), this largest core model ought to coincide with $\mathsf{HOD}$ itself. I'm sure there are more serious and sophisticated reasons as well.
Aug 22, 2013 at 2:44 comment added Andrés E. Caicedo @EverettPiper Here is a weak reason: The model $\mathsf{HOD}$ of natural models of determinacy certainly has this property. This was shown by Steel (and extended by Woodin) for $L(\mathbb R)$, and has since been established for much larger models; in fact, the possibility of such a description of $\mathsf{HOD}$ is key in recent developments in descriptive inner model theory. Under very large cardinals, we expect "higher order instances" of results that hold under determinacy to be true.
Aug 21, 2013 at 12:00 comment added Everett Piper @AndresCaicedo Would you mind elaborating on the expectation that an initial segment of HOD be "core like"? I ran across a similar sentiment a couple of years ago but I was unable to see why the person making this claim would have this expectation.
Aug 19, 2013 at 21:18 answer added Joel David Hamkins timeline score: 8
Aug 19, 2013 at 18:56 comment added Andrés E. Caicedo @MonroeEskew It seems a natural problem. Under appropriate assumptions, we would expect an initial segment of $\mathsf{HOD}$ (certainly beyond $\mathsf{HOD}\cap V_{\omega_1}$) to be "core like", in particular to satisfy $\mathsf{GCH}$. This is a natural test question to try to clarify what those additional assumptions ought to require.
Aug 19, 2013 at 18:37 comment added Monroe Eskew What is the motivation for this question?
Aug 19, 2013 at 14:25 comment added Joel David Hamkins A more fundamental question is what does $\text{HOD}^{V[G]}$ mean exactly? The usual definition of HOD makes use of reflection to levels $V_\theta$ of the von Neumann hierarchy, which are ordinal definable, but since we lack power sets in $V[G]$ we do not have this hierarchy there. So what is $W$ exactly?
Aug 19, 2013 at 9:52 comment added Asaf Karagila (In my first comment I meant $H(\omega_1)^{V[G]}$, not $V_{\omega_1}$)
Aug 19, 2013 at 9:42 comment added Asaf Karagila There is also a paper by Roguski called "Hartogs's numbers and axiom of power-set" which is impossible to find online (and the library at HUJI, where the paper can be found, is closed this week). I don't recall the exact construction the author uses, but it might be relevant.
Aug 19, 2013 at 9:39 comment added Asaf Karagila Perhaps a good test case would be to collapse an inaccessible $\kappa$ like that, and consider $V_{\omega_1}^{V[G]}$.
Aug 19, 2013 at 9:20 history asked Mohammad Golshani CC BY-SA 3.0