Timeline for A sufficient condition for a space to be an Eilenberg-Maclane space
Current License: CC BY-SA 3.0
3 events
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| Aug 16, 2013 at 23:07 | comment | added | Eric Wofsey | The way I imagine proving the "not hard to see" part is to show (eg, by induction on the number of cells in $K$) that if $K$ contains the singular point of $X$, $K$ is contained in a contractible subset whose boundary is a union of two loops contained in the 1-skeleton of $X$. It is quite possible that you can do away with the finiteness assumption with a little more work. | |
| Aug 16, 2013 at 23:00 | comment | added | Vidit Nanda | Where do you use the finiteness of $K$ in the part that "is not hard to see"? | |
| Aug 16, 2013 at 21:47 | history | answered | Eric Wofsey | CC BY-SA 3.0 |