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replaced non-applicable tag; corrected typos and minor grammatical mistakes to improve readability
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Ricardo Andrade
Ricardo Andrade
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Discrete subgroupsubgroups of products of SU(2)

It is knowknown that there are -up to conjugation- 5 classes of discrete subgroups of SU(2).One One way to show this is by means of the MckayMcKay correspondence. MyMy question is more regarding porductsproducts of $SU(2)$, say with $n$ factors. Well, since I am definitely not familiar with the correspondence above, I would like to ask wheterwhether I have any hope to classify all finite subgroups of the product of 2 or 3 timescopies of $SU(2)$ by following the same line of thoughtsthought. Or in case someone knows a more economical alternative, I would be very happy to listen to it.

Discrete subgroup products of SU(2)

It is know that there are -up to conjugation- 5 classes of discrete subgroups of SU(2).One way to show this is by means of the Mckay correspondence. My question is more regarding porducts of $SU(2)$ say with $n$ factors. Well, since I am definitely not familiar with the correspondence above, I would like to ask wheter I have any hope to classify all finite subgroups of 2 or 3 times $SU(2)$ by following the same line of thoughts. Or in case someone knows a more economical alternative, I would be very happy to listen to it.

Discrete subgroups of products of SU(2)

It is known that there are -up to conjugation- 5 classes of discrete subgroups of SU(2). One way to show this is by means of the McKay correspondence. My question is more regarding products of $SU(2)$, say with $n$ factors. Well, since I am definitely not familiar with the correspondence above, I would like to ask whether I have any hope to classify all finite subgroups of the product of 2 or 3 copies of $SU(2)$ by following the same line of thought. Or in case someone knows a more economical alternative, I would be very happy to listen to it.

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user38651
user38651
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Discrete subgroup products of SU(2)

It is know that there are -up to conjugation- 5 classes of discrete subgroups of SU(2).One way to show this is by means of the Mckay correspondence. My question is more regarding porducts of $SU(2)$ say with $n$ factors. Well, since I am definitely not familiar with the correspondence above, I would like to ask wheter I have any hope to classify all finite subgroups of 2 or 3 times $SU(2)$ by following the same line of thoughts. Or in case someone knows a more economical alternative, I would be very happy to listen to it.