Timeline for a question on the space of divisors on a curve
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 15, 2013 at 14:17 | history | edited | rfauffar | CC BY-SA 3.0 |
I corrected a critical mistake that completely changed the outcome of the answer.
|
| Aug 15, 2013 at 14:12 | comment | added | rfauffar | Yes of course! Thanks for the correction, I'll change it now. | |
| Aug 15, 2013 at 13:25 | comment | added | S. Carnahan♦ | This minor misunderstanding should be relatively easy to correct. For each $k$, let $\operatorname{Unt}_k(X)$ be the space of divisors on which the sum of untransversal points is equal to $k$. Then the space in question is the complement of the closed set $\bigcup_{N<k\leq d} \operatorname{Unt}_k(X)$. | |
| Aug 15, 2013 at 8:22 | comment | added | prochet | it's not closed because it contains all points such that $m_{x}(D)\leq 1$ | |
| Aug 15, 2013 at 0:28 | history | answered | rfauffar | CC BY-SA 3.0 |