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Aug 16, 2013 at 10:20 vote accept Oleg Karpin
Aug 11, 2013 at 20:08 answer added abz timeline score: 4
Aug 11, 2013 at 11:15 history edited Oleg Karpin CC BY-SA 3.0
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Aug 11, 2013 at 11:08 comment added abz Yes, it's induced by f, and so compatible with Galois.
Aug 11, 2013 at 11:08 comment added Chandan Singh Dalawat The isogeny $f$ will be compatible with the Galois actions if it is a $K$-isogeny.
Aug 11, 2013 at 11:04 comment added Oleg Karpin Thanks for pointing this out. A priori this isomorphism is an isomorphism of abstract groups, is this isomorphism in addition compatible with Galois actions? If yes, this would imply $K(A[\ell])=K(A'(\ell))$ for all $\ell\nmid \deg(f)$?
Aug 11, 2013 at 10:59 comment added naf If $f:A \to A'$ is an isogeny, then $f$ induces an isomorphism from $A[l]$ onto $A'[l]$ for any $l$ prime to the degree of $f$.
Aug 11, 2013 at 10:55 review First posts
Aug 11, 2013 at 10:57
Aug 11, 2013 at 10:39 history asked Oleg Karpin CC BY-SA 3.0