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Aug 9, 2013 at 19:54 comment added Peter Michor Maybe, you should add the requirement that each $G$-orbit (with subspace topology) is homeomorphic to $G$.
Aug 9, 2013 at 8:46 answer added Misha timeline score: 5
Aug 9, 2013 at 5:15 comment added Peter Michor Did you try to adapt Palais' proof of the slice theorem? MR0126506 (23 #A3802) Palais, Richard S. On the existence of slices for actions of non-compact Lie groups. Ann. of Math. (2) 73 1961 295–323.
Aug 9, 2013 at 4:37 history edited David Carchedi CC BY-SA 3.0
added 105 characters in body
Aug 9, 2013 at 3:27 comment added Misha Think of the case when $G$ is finite and acts simply transitively.
Aug 8, 2013 at 22:21 comment added Vít Tuček Maybe you can use metrization theorem on the quotient and try to build a metric on $Q$ out of it and metric on $G$?
Aug 8, 2013 at 22:08 comment added Mariano Suárez-Álvarez I guess the ending not in the parenthetical remark in your title is a typo?
Aug 8, 2013 at 21:13 history asked David Carchedi CC BY-SA 3.0