Timeline for Two cubes in unit cube
Current License: CC BY-SA 3.0
7 events
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| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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| Aug 9, 2013 at 22:15 | comment | added | Wlodek Kuperberg | @user64494 In case each of the two small cubes is homothetic to the large one, the inequality in question is obvious. | |
| Aug 7, 2013 at 16:31 | comment | added | user64494 | @ asatzhh : You are right. | |
| Aug 7, 2013 at 16:30 | comment | added | asatzhh | @user64494 where is $(\frac{1}{2},\dots,\frac{1}{2})$ if $a>\frac{1}{2}$? | |
| Aug 7, 2013 at 16:24 | comment | added | asatzhh | @user64494 since they having non-overlapping interiors,$a\le\frac{1}{2}$. | |
| Aug 7, 2013 at 16:22 | comment | added | user64494 | You claim the inequality: $a+b \le 2^{\frac {n-1} n }$. A simple example of the cubes $[0,a]^n$ and $[1-a,1]^n$ contradicts it. I wonder the upvoter. | |
| Aug 7, 2013 at 16:12 | history | answered | asatzhh | CC BY-SA 3.0 |