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Aug 7, 2013 at 15:36 comment added Mark Gross Francesco, that's right.
Aug 7, 2013 at 15:25 comment added Francesco Polizzi Blowing-up the ODP one obtains as exceptional divisor a smooth quadric in $\mathbb{P}^3$. If there is no algebraic small resolution then the two rulings of this quadric must be numerically equivalent in the blown-up threefold, right?
Aug 7, 2013 at 15:25 comment added Rhys Davies Thanks Mark, that's exactly what I was after. I was actually reading Friedman's paper, but with my poor grasp of deformation theory, I hadn't managed to extract what I needed!
Aug 7, 2013 at 15:21 vote accept Rhys Davies
Aug 7, 2013 at 15:03 history answered Mark Gross CC BY-SA 3.0