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Timeline for Analytic uniformization

Current License: CC BY-SA 3.0

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Aug 27, 2013 at 22:37 comment added 喻 良 You are right. I corrected the typo. The existence of $A$ follows from a well known fact that there is a $\Sigma^1_1$ set which does not contain a hyperarithmetic real.
Aug 27, 2013 at 22:35 history edited 喻 良 CC BY-SA 3.0
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Aug 27, 2013 at 15:02 vote accept jonathanverner
Aug 27, 2013 at 15:01 comment added jonathanverner I assume that the first formula should read $A\subseteq 2^{<\omega}\times\omega^{<\omega}$... Also, does the existence of $A$ follow from some theorem or should it be obvious (sorry, I am not very fluent in descriptive set theory let alone effective descriptive ST).
Aug 7, 2013 at 11:06 history answered 喻 良 CC BY-SA 3.0