Timeline for Hilbert polynomials on a scheme
Current License: CC BY-SA 3.0
11 events
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| Aug 8, 2013 at 8:55 | history | edited | s4o673wn | CC BY-SA 3.0 |
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| Aug 8, 2013 at 8:18 | comment | added | S. Carnahan♦ | Regarding your flag, I am somewhat hesitant to delete this question, because the answer is rather informative. You are welcome to edit your question to make it clear exactly how you were confused. | |
| Aug 7, 2013 at 12:07 | vote | accept | s4o673wn | ||
| Aug 7, 2013 at 12:07 | vote | accept | s4o673wn | ||
| Aug 7, 2013 at 12:07 | |||||
| Aug 7, 2013 at 10:54 | history | edited | s4o673wn | CC BY-SA 3.0 |
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| Aug 7, 2013 at 10:29 | history | edited | s4o673wn | CC BY-SA 3.0 |
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| Aug 7, 2013 at 10:20 | review | Close votes | |||
| Aug 9, 2013 at 16:51 | |||||
| Aug 7, 2013 at 9:47 | answer | added | Jason Starr | timeline score: 3 | |
| Aug 7, 2013 at 9:30 | comment | added | Jack Huizenga | I'm not sure what your question is. When discussing Hilbert polynomials it is usually understood that $X$ is projective with very ample line bundle $\mathcal O(1)$. In the relative setting, you would need a projective $X/S$ with a very ample line bundle $\mathcal O(1)$ on $X$ relative to $S$. This restricts to a very ample line bundle on each fiber, and you define the Hilbert polynomial in terms of the restricted line bundle. | |
| Aug 7, 2013 at 9:15 | review | First posts | |||
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| Aug 7, 2013 at 8:59 | history | asked | s4o673wn | CC BY-SA 3.0 |