Timeline for On a characterization of the Gårding subspace of the left regular representation of reals
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Aug 13, 2013 at 14:54 | vote | accept | Murat Güngör | ||
| Aug 13, 2013 at 14:54 | comment | added | Murat Güngör | By the way, I realized that the inclusion $\supseteq$ in my question (more generally, the inclusion $\supseteq$ in the first displayed equality on p. 114 of Poulsen's) follows easily from Lemma 3.13 of Knapp's as well. | |
| Aug 13, 2013 at 14:50 | comment | added | Murat Güngör | You are right. My computation above is definitely incorrect. Thanks for the clarification. | |
| Aug 13, 2013 at 14:16 | comment | added | Francois Ziegler | @MuratGüngör: Yes, I am sure. (Your formula for $(Xf)(x)$ has a stray $x$; compare my edited answer.) | |
| Aug 13, 2013 at 14:14 | history | edited | Francois Ziegler | CC BY-SA 3.0 |
added 602 characters in body
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| Aug 12, 2013 at 14:06 | comment | added | Murat Güngör | Thank you for the reference, but are you sure that Poulsen's results imply my equality? In his notation (see p. 113), we have $(Xf)(x)=-Xxf'(x)$ for $X\in\mathrm{Lie}(\mathbb{R})$, so $X$ is not simply the derivative operator; consequently, the right-hand side of the first displayed equality on his p. 114 is not my right-hand side above. | |
| Aug 7, 2013 at 20:22 | history | edited | Francois Ziegler | CC BY-SA 3.0 |
better link
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| Aug 6, 2013 at 18:30 | history | answered | Francois Ziegler | CC BY-SA 3.0 |