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when toggle format what by license comment
Aug 6, 2013 at 1:10 history edited Benjamin Steinberg CC BY-SA 3.0
Fixed missing dollar sign
Aug 3, 2013 at 20:35 history edited Igor Rivin CC BY-SA 3.0
added more thoughts.
Aug 3, 2013 at 3:41 comment added Michael Zieve I'm sure that by "mutually algebraically independent" the OP meant that there is no nonzero $H(x_1,\dots,x_k,y_1,\dots,y_k)\in\mathbb{Z}[x_1,x_2,\dots,x_k,y_1,y_2,\dots,y_k]$ such that $H(\alpha_1,\alpha_2,\dots,\alpha_k,\beta_1,\beta_2,\dots,\beta_k)=0$. That's the standard definition of algebraic independence over $\mathbb{Q}$.
Aug 3, 2013 at 0:50 history answered Igor Rivin CC BY-SA 3.0