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Aug 8, 2013 at 14:30 vote accept Anette
Aug 2, 2013 at 18:26 comment added Dag Oskar Madsen To make my previous comment more precise, I should add that if $M$ and $N$ are pure of the same weight, then you can have $\mathrm{ext}^0_A (M,N) \neq 0$ also in the semisimple case.
Aug 2, 2013 at 14:10 comment added Anette @Dietrich Thanks for your responses. As to why I deleted the question on math stack, when I deleted it there were no comments or answers to the question and I thought it would be easier to just have one version of the question up.
Aug 2, 2013 at 13:41 comment added Dag Oskar Madsen Let $M$ and $N$ be pure. In the semisimple case $ext^i_A (M,N) = 0$ for all $i$. In the Koszul case $ext^i_A (M,N) = 0$ for all $i$ except possibly one value. I guess this is what they mean by the phrase in the title.
Aug 2, 2013 at 13:23 comment added Dietrich Burde Why did you delete your question on math stack ?
Aug 2, 2013 at 13:23 answer added Dietrich Burde timeline score: 4
Aug 2, 2013 at 12:24 review First posts
Aug 2, 2013 at 12:30
Aug 2, 2013 at 12:06 history asked Anette CC BY-SA 3.0