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Nov 15, 2014 at 14:45 history edited Francesco Polizzi CC BY-SA 3.0
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Jul 30, 2013 at 11:46 comment added Francesco Polizzi If one has two irreducible curves $C$, $D$ on a smooth complex projective surface, with $C \neq D$, then $C \cdot D$ is the number of intersections of $C$ and $D$ (counted with multiplicities). In particular $C \cdot D \geq 0$. Then if $C \cdot D <0$ it follows that $C$ and $D$ necessarily have some component in common (and such component has negative self-intersection). This explains (1) and also (2). Notice that in this example one does not need to know all the effective divisors on $X$.
Jul 30, 2013 at 10:50 comment added Li Yutong Thank you so much! I have two further questions regard your answer: (1) Why you claim " since $C\cdot D=-1$, ..., it follows that $C$ is a component of D" ?(2) Why $C$ has nonnegative intersection with any irreducible curve differ from $C$? I think the two questions are essentially the same: how to describe the effective divisors on $X$?
Jul 30, 2013 at 10:38 vote accept Li Yutong
Jul 30, 2013 at 10:31 history edited Francesco Polizzi CC BY-SA 3.0
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Jul 30, 2013 at 10:10 history edited Francesco Polizzi CC BY-SA 3.0
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Jul 30, 2013 at 10:03 history edited Francesco Polizzi CC BY-SA 3.0
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Jul 30, 2013 at 9:44 history edited Francesco Polizzi CC BY-SA 3.0
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Jul 30, 2013 at 9:37 history answered Francesco Polizzi CC BY-SA 3.0