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Jul 29, 2013 at 18:16 comment added Stephen Sturgeon I suggest comparing $e^{-x^2n^2/2+2\ln(n)}$ and $e^{-x^2n/2}$. I just worked it out and it shows that you can use a strict comparison for $x$ sufficiently large.
Jul 29, 2013 at 17:40 history answered Stephen Sturgeon CC BY-SA 3.0