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Jul 28, 2013 at 8:31 comment added Mohammad Khosravi Yes! As I thought more, I saw that the structure of $A$ is just saying $A$ is symmetric and $A 1_n = 0$ where $1_n$ is $n\times 1$ vector of $1$s, which I doubt they provides significant information regarding positive (semi-)definiteness of $A$.
Jul 28, 2013 at 1:32 history answered Igor Rivin CC BY-SA 3.0