Timeline for Is the fundamental group of $II_{1}$ factors invariant under a relation?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 28, 2013 at 17:58 | vote | accept | Sebastien Palcoux | ||
| Jul 28, 2013 at 17:20 | comment | added | Jesse Peterson | @SébastienPalcoux: This is because if $u \in L(\mathbb F_\infty) \subset M * L(\mathbb F_\infty)$ is a unitary with trace $0$ then $M$ is in free position from $u M u^*$, hence $M * M \cong W^*( M, u M u^* ) \subset M * L(\mathbb F_\infty) \cong M$. | |
| Jul 28, 2013 at 8:42 | comment | added | Sebastien Palcoux | Thank you very much @JessePeterson ! I learn a lot by reading your answer. The only point I don't understand is : why $M \simeq M \star L(\mathbb{F}_{\infty}) \Rightarrow M \star M \hookrightarrow M$ ? | |
| Jul 27, 2013 at 22:14 | history | answered | Jesse Peterson | CC BY-SA 3.0 |