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Sep 23, 2013 at 22:49 answer added Lucia timeline score: 11
Sep 2, 2013 at 19:02 vote accept CommunityBot
Jul 30, 2013 at 0:41 answer added S. Carnahan timeline score: 4
Jul 29, 2013 at 4:37 history edited Andrej Bauer CC BY-SA 3.0
Replaced | with \mid for improved spacing.
Jul 29, 2013 at 3:14 answer added Noam D. Elkies timeline score: 6
Jul 28, 2013 at 19:32 answer added Will Sawin timeline score: 3
Jul 28, 2013 at 10:27 answer added Aaron Meyerowitz timeline score: 2
Jul 27, 2013 at 20:43 comment added Kevin P. Costello A slightly better lower bound for some $n$: Take $n=k!$, so that $n!=(n-1)!k!$
Jul 27, 2013 at 16:34 answer added GH from MO timeline score: 11
Jul 27, 2013 at 15:11 answer added Seva timeline score: 16
Jul 27, 2013 at 14:51 comment added Seva Well, you cannot have a much smaller bound since you can have $a+b=n+1$ (take $a=n$ and $b=1$).
Jul 27, 2013 at 14:43 history asked user30230 CC BY-SA 3.0