Timeline for How $a+b$ can grow when $a!b! \mid n!$
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Sep 23, 2013 at 22:49 | answer | added | Lucia | timeline score: 11 | |
Sep 2, 2013 at 19:02 | vote | accept | CommunityBot | ||
Jul 30, 2013 at 0:41 | answer | added | S. Carnahan♦ | timeline score: 4 | |
Jul 29, 2013 at 4:37 | history | edited | Andrej Bauer | CC BY-SA 3.0 |
Replaced | with \mid for improved spacing.
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Jul 29, 2013 at 3:14 | answer | added | Noam D. Elkies | timeline score: 6 | |
Jul 28, 2013 at 19:32 | answer | added | Will Sawin | timeline score: 3 | |
Jul 28, 2013 at 10:27 | answer | added | Aaron Meyerowitz | timeline score: 2 | |
Jul 27, 2013 at 20:43 | comment | added | Kevin P. Costello | A slightly better lower bound for some $n$: Take $n=k!$, so that $n!=(n-1)!k!$ | |
Jul 27, 2013 at 16:34 | answer | added | GH from MO | timeline score: 11 | |
Jul 27, 2013 at 15:11 | answer | added | Seva | timeline score: 16 | |
Jul 27, 2013 at 14:51 | comment | added | Seva | Well, you cannot have a much smaller bound since you can have $a+b=n+1$ (take $a=n$ and $b=1$). | |
Jul 27, 2013 at 14:43 | history | asked | user30230 | CC BY-SA 3.0 |