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Aug 1, 2013 at 16:50 vote accept Boris Novikov
Aug 1, 2013 at 16:44 answer added Misha timeline score: 2
Jul 29, 2013 at 16:57 comment added Boris Novikov @Misha: Thank you very much. I think for me now it is enough. Would you like to transform this remark into an answer?
Jul 29, 2013 at 4:13 comment added Misha If I understand it correctly, what Hanna Neumann defined is not a special case graph of groups, but of what is now called a "complex of groups". Search for "complex of semigroups" returned nothing. My guess then is that you are on your own. My suggestion is to look for a CAT(0)-concept which might work in this context and would yield a "developable complex" of semigroups and guarantee, say, that vertex semigroups are embedded. Reading first Gersten and Stallings (for triangles of groups) and then Bridson and Haefliger (in general) might be a good start.
Jul 28, 2013 at 15:14 answer added user6976 timeline score: 1
Jul 27, 2013 at 17:01 answer added Anton Klyachko timeline score: 0
Jul 27, 2013 at 16:09 comment added Boris Novikov @ Mark Sapir: Mark, all of these references deal with the case when there is only one amalgamated subsemigroup -- the intersection of all semigroups. I need the case when we have a family of amalgamated subsemigroups -- the intersections of pairs of semigroups.
Jul 27, 2013 at 16:00 comment added user6976 @Boris: What do you want to know and cannot find from the 162 references given by googling "amalgam of semigroups"?
Jul 27, 2013 at 15:42 comment added Boris Novikov @Misha: Misha, spasibo. This information is useful for me also.
Jul 27, 2013 at 15:08 comment added Misha @BorisNovikov: Boris, I know nothing about semigroups, but for groups, $\pi_1$ of a finite graph of groups can be always reduced to an iterated amalgam/HNN extension where on each step only one subgroup is involved. For countable graphs one can use this + direct limit.
Jul 27, 2013 at 14:28 comment added Boris Novikov @ Benjamin Steinberg: Benjamin, thank you, but I am interested just in the case of several subsemigroups.
Jul 27, 2013 at 14:14 comment added Benjamin Steinberg Yes people have although most of the attention has been focused on one subsemigroup.
Jul 27, 2013 at 13:43 history edited Boris Novikov CC BY-SA 3.0
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Jul 27, 2013 at 8:45 history edited Boris Novikov
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Jul 27, 2013 at 8:39 history edited Boris Novikov CC BY-SA 3.0
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Jul 27, 2013 at 8:35 history edited Ricardo Andrade
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Jul 27, 2013 at 7:32 history asked Boris Novikov CC BY-SA 3.0