Timeline for Two infinite dimensional algebras such that the center of their tensor product is bigger than the tensor product of their centers
Current License: CC BY-SA 3.0
7 events
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| Feb 7, 2021 at 14:14 | comment | added | Captain Lama | I think @Ben is correct, and this example does not work. Usually I wouldn't write a comment just to say I agree with someone, but given the number of upvotes for this answer it can't hurt to attract some attention to its incorrectness. | |
| Apr 17, 2014 at 11:17 | comment | added | Ben | Isn't $z=0$? The tensor product is over $k[x]$, so $u_1 x^{-1}\otimes xy$ is just $u_1 \otimes y$. I got doubtful because your Argument would in fact work for $B=k[x,y]$, and I'm sure that can't be. | |
| Jul 25, 2013 at 12:16 | history | edited | eithil | CC BY-SA 3.0 |
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| Jul 25, 2013 at 11:02 | comment | added | eithil | Good point; I'm so used to "algebra" meaning $k$-algebra I completely forgot about $R$-algebras. I've updated my post with an $R$-algebra example that hopefully works. | |
| Jul 25, 2013 at 11:01 | history | edited | eithil | CC BY-SA 3.0 |
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| Jul 24, 2013 at 11:08 | comment | added | Maximiliano Valle | I think that the key point is that you assume that the algebra is over a field instead of a commutative ring. | |
| Jul 24, 2013 at 10:17 | history | answered | eithil | CC BY-SA 3.0 |