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Jul 23, 2013 at 13:24 vote accept Jean Raimbault
Jul 23, 2013 at 11:44 comment added Noam D. Elkies One must also consider Pell equations $t^2 - u^2 d = -4$ (and also $\pm 4i$ and $\pm 2 \pm \sqrt{-12}$ for $D=-4$ and $D=-3$ respectively). But these do not materially affect the answer.
Jul 23, 2013 at 11:42 answer added Noam D. Elkies timeline score: 8
Jul 23, 2013 at 7:45 history edited Jean Raimbault CC BY-SA 3.0
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Jul 23, 2013 at 7:44 comment added Jean Raimbault @KConrad: quartic it is, then.
Jul 23, 2013 at 7:43 comment added Jean Raimbault @anton: yes, $|\varepsilon_F|$ depends only on $d$; $D$ determines the range of values of $d$.
Jul 23, 2013 at 2:56 comment added KConrad I think it might be better to call these fields quartic rather than biquadratic: quartic definitely means "degree 4", while biquadratic suggests a specific type of quartic extension, namely a composite of two quadratic extensions (so of the form ${\mathbf Q}(\sqrt{a},\sqrt{b})$ with rational $a$ and $b$).
Jul 22, 2013 at 16:39 comment added user1688 Yes, but then $\varepsilon_F$ depends only on $d$ and not on $D$?
Jul 22, 2013 at 15:38 comment added Jean Raimbault I believe that "fundamental discriminant" is the standard term for the set of these integers which are quadratic residues mod 4 but not squares in ${\mathcal O}_D$ (I added "in ${\mathcal O}_D$" to put emphasis on the dependancy on $D$).
Jul 22, 2013 at 14:40 comment added user1688 What do you mean by "fundamental discriminant"? Usually, it's an integer, so that would mean that always all fd are in ${\cal O}_D$.
Jul 22, 2013 at 13:57 history asked Jean Raimbault CC BY-SA 3.0