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Jul 21, 2013 at 20:37 comment added Andrés E. Caicedo (Joel, St.D., I've emailed the file to both of you.)
Jul 21, 2013 at 11:51 comment added Stamatis Dimopoulos @Joel David Hamkins and Andres Caicedo: I sent you both e-mails. Now I want to ask something else. As I understand from the first solution, it suffices to show that no condition forces that $\dot{X}$ is not decided by $W$. But could have this immediately, since the set $$\{p\in P:p\Vdash \dot{X}\in \dot{W}\lor p\Vdash \dot{X}\not\in \dot{W}\}$$ is always dense?
Jul 21, 2013 at 1:39 comment added Andrés E. Caicedo Joel, will do, once Francisco is in bed. St.D., please email me, so I have an email address to send you the file.
Jul 21, 2013 at 0:54 comment added Joel David Hamkins Andres---that is fine. Could you kindly email me a copy also? (sigh...) Also, St.D., if you send me an email, I can also send you another relevant reference.
Jul 21, 2013 at 0:48 comment added Andrés E. Caicedo @St.D. You may email Joel about this. Or, if he doesn't have an online copy to send you, and he is fine with this, I could email you a pdf of a copy I scanned years ago.
Jul 21, 2013 at 0:48 comment added Joel David Hamkins You're welcome, St. D. And thanks for the reference, Andres!
Jul 21, 2013 at 0:46 comment added Stamatis Dimopoulos Thanks for the answer. @Andres Caicedo: Is there a link for the thesis? In Dr. Hamkin's website, the text is not available.
Jul 21, 2013 at 0:33 vote accept Stamatis Dimopoulos
Jul 21, 2013 at 0:22 comment added Andrés E. Caicedo A nice reference to add here is Joel's PhD thesis, Lifting and extending measures by forcing; fragile measurability, UC Berkeley, 1994.
Jul 20, 2013 at 23:34 history edited Joel David Hamkins CC BY-SA 3.0
added 876 characters in body
Jul 20, 2013 at 23:25 history answered Joel David Hamkins CC BY-SA 3.0