Timeline for Surjectivity of frobenius
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Jul 20, 2013 at 16:41 | vote | accept | Lan | ||
Jul 20, 2013 at 13:58 | comment | added | user36938 | Very good. Strictly speaking, this gives $x = {y'}^p + p^{1-1/p}z$, but surjectivity of Frobenius on $\overline{R}/(p^{\varepsilon})$ for some $0 < \varepsilon \le 1$ implies the same for $\overline{R}/(p)$ after finitely many iterations (depending on $\varepsilon$). | |
Jul 19, 2013 at 19:58 | review | First posts | |||
Jul 19, 2013 at 20:00 | |||||
Jul 19, 2013 at 19:41 | history | answered | almostuser | CC BY-SA 3.0 |