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Jul 20, 2013 at 0:05 comment added user36938 @Jeremey: Sure, all I meant is that what looks like a "square root" from one point of view may be a "coordinate" from another; for the plane curve $C$ defined by $y^2 = f(x)$ one could say that the map $y:C \rightarrow \mathbf{A}^1$ is $P \mapsto \sqrt{f(x(P))}$.
Jul 19, 2013 at 19:25 comment added Jérémy Blanc No, square roots are not allowed for a rational map. If you want a rational map from a variety $X$ to a variety $Y$, the image of a point $x\in X$ should depend algebraically from the coordinates in $X$ (i.e. be quotient of polynomials).
Jul 19, 2013 at 3:40 comment added user36938 As you know, square roots would be OK - we would just call it ``$y$'' and write $y^2 = f(x)$, etc. Exp and log would be another matter. :)
Jul 18, 2013 at 19:02 history answered Jérémy Blanc CC BY-SA 3.0