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S Jul 6, 2014 at 9:03 history suggested Sergiy Kozerenko CC BY-SA 3.0
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Jul 6, 2014 at 9:01 review Suggested edits
S Jul 6, 2014 at 9:03
Sep 12, 2013 at 13:23 review Suggested edits
Sep 12, 2013 at 13:29
Jul 19, 2013 at 3:27 vote accept Anand
Jul 17, 2013 at 6:55 comment added Aaron Meyerowitz Very nice. So in a graph with $n$ vertices and minimum degree $\delta$ every edge is in at least $2\delta-n$ triangles. It is possible to have $n=2\delta$ and no triangles but if $n \le 2\delta-1$ then every edge is in a triangle so there are lots of triangles.
Jul 17, 2013 at 6:49 comment added The Masked Avenger Indeed, a couning argument might show something mildly stronger: a non bipartite graph which is triangle free has either a minimum degree less than 2n/5, or the graph is 2n/5-regular. This could well be part of an undergraduate graph theory course.
Jul 17, 2013 at 5:37 comment added The Masked Avenger Given the elementary nature of the analysis in this answer, I would like to see the corollary mentioned in the question and how it is more interesting than the supposedly weaker alternative.
Jul 17, 2013 at 5:32 history answered The Masked Avenger CC BY-SA 3.0