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Jul 20, 2013 at 19:18 vote accept mathSt
Jul 18, 2013 at 0:18 comment added mathSt I posted a reply as an "answer". It was too long for fitting here.
Jul 17, 2013 at 2:44 comment added Tyler Kelly Oops! Yeah the result being discussed here is usually called the Griffiths-Dolgachev-Steenbrink formula.
Jul 17, 2013 at 2:42 comment added Charles Siegel It's worth noting that you should expect a formula like the one Dolgachev wrote, due to the formula of Griffiths that for a hypersurface of dimension $n$ and degree $d$ has $H^{p,n-p}\cong R_{(n-p+1)d-(n+2)}$, where $R$ is the Jacobian ring, essentially the exact formula above, corrected for the weights.
Jul 17, 2013 at 2:30 review First posts
Jul 17, 2013 at 2:33
Jul 17, 2013 at 2:15 history answered Tyler Kelly CC BY-SA 3.0