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Jul 19, 2013 at 22:27 comment added The Masked Avenger Thanks for accepting the answer. I would still like to know more of the motivation and the corollary, even if it did not turn out to be much more interesting.
Jul 19, 2013 at 3:27 vote accept Anand
Jul 17, 2013 at 9:17 review Close votes
Jul 17, 2013 at 11:36
Jul 17, 2013 at 5:32 answer added The Masked Avenger timeline score: 5
Jul 17, 2013 at 4:39 answer added Aaron Meyerowitz timeline score: 3
Jul 17, 2013 at 2:00 answer added Igor Rivin timeline score: 3
Jul 17, 2013 at 0:08 comment added The Masked Avenger It might be useful to consider two vertices of minimum degree joined by an edge. If the graph is triangle free that gets a bound close to what is suggested, but there is more lurking behind the example.
Jul 16, 2013 at 23:25 comment added Aaron Meyerowitz You want an upper bound on the minimum degree. The average degree is larger (or at least as large.) Look for upper bounds on the number of edges in a triangle free graph with $n$ vertices (complete bipartite...) and use that.
Jul 16, 2013 at 23:09 review First posts
Jul 16, 2013 at 23:18
Jul 16, 2013 at 22:51 history asked Anand CC BY-SA 3.0