Timeline for Finite extension of a field [closed]
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Jul 15, 2013 at 21:44 | history | closed |
Steven Landsburg Karl Schwede Andrey Rekalo Martin Brandenburg Jack Huizenga |
Not suitable for this site | |
| Jul 15, 2013 at 20:41 | comment | added | Martin Brandenburg | Voted to close because this well-known fact is contained in every good introduction to algebraic geometry or commutative algebra - definitely not research level. | |
| Jul 15, 2013 at 18:08 | comment | added | Karl Schwede | This is reduces to a basic fact about integral domains and when finite extensions can be fields. A basic book on algebra (for example Dummit and Foote) has the references you want. | |
| Jul 15, 2013 at 16:45 | vote | accept | user46336 | ||
| Jul 15, 2013 at 16:35 | answer | added | Steven Landsburg | timeline score: 1 | |
| Jul 15, 2013 at 16:06 | comment | added | user46336 | Why finiteness of $Q(A/p)$ implies finiteness of $A/p$? | |
| Jul 15, 2013 at 16:05 | review | Close votes | |||
| Jul 15, 2013 at 21:46 | |||||
| Jul 15, 2013 at 16:00 | comment | added | Keenan Kidwell | Yes. If $p$ is maximal, then $A/p$ is finite over $k$ by the Nullstellensatz. Conversely, if $A/p$ is finite over $k$, then $A/p$ must be a field, so $p$ is maximal. | |
| Jul 15, 2013 at 15:52 | comment | added | Steven Landsburg | I've deleted my earlier comment, which was based on a misreading of the question. My apologies. | |
| Jul 15, 2013 at 15:45 | review | First posts | |||
| Jul 15, 2013 at 15:49 | |||||
| Jul 15, 2013 at 15:29 | history | asked | user46336 | CC BY-SA 3.0 |