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Jul 15, 2013 at 6:17 answer added Mark Grant timeline score: 3
Jul 15, 2013 at 2:18 comment added Peter Crooks I would like to investigate non-equivariant ways to describe the topology of $X$. Anything about the cohomology of $X$ (or how I might find it) would be welcome, for instance.
Jul 15, 2013 at 2:12 history edited Peter Crooks CC BY-SA 3.0
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Jul 15, 2013 at 2:11 comment added Peter Crooks Yes, that's quite right. The cohomology of any manifold can be realized as the equivariant cohomology of a $T$-manifold on which $T$ acts freely. However, I am not particularly interested in $H_T^*(X)$, but in $H^*(X)$. I will amend my question accordingly.
Jul 15, 2013 at 1:35 comment added Jason Starr What type of result are you looking for? Obviously for every compact, connected, smooth manifold $Q$, taking $X=Q\times T$ with the obvious $T$-action, then $H^*_T(X)$ equals $H^*(Q)$. So, in this sense, there are no further restrictions on $H^*_T(X)$.
Jul 14, 2013 at 22:38 history edited Peter Crooks CC BY-SA 3.0
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Jul 14, 2013 at 19:28 history edited Peter Crooks CC BY-SA 3.0
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Jul 14, 2013 at 19:16 history edited Peter Crooks CC BY-SA 3.0
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Jul 14, 2013 at 19:10 history asked Peter Crooks CC BY-SA 3.0