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Jul 12, 2013 at 4:47 answer added Bruno Le Floch timeline score: 10
S Jul 11, 2013 at 5:40 history suggested Amritanshu Prasad CC BY-SA 3.0
displayed the matrices
Jul 11, 2013 at 5:26 review Suggested edits
S Jul 11, 2013 at 5:40
Jul 10, 2013 at 22:13 answer added Dietrich Burde timeline score: 13
Jul 10, 2013 at 19:16 answer added Steve Huntsman timeline score: 11
Jul 10, 2013 at 18:08 answer added Igor Rivin timeline score: 14
Jul 10, 2013 at 18:02 comment added Neil Strickland When $n=5$, the numerator of the determinant is divisible by the large prime $179357$. This implies that, unlike the Hilbert matrix, there is no simple formula for the determinant as a ratio of products of factorials.
Jul 10, 2013 at 18:01 comment added John Wiltshire-Gordon You can give a formula for the determinant using the Jacobi-Trudi identities
Jul 10, 2013 at 17:55 review First posts
Jul 10, 2013 at 18:01
Jul 10, 2013 at 17:46 comment added Clément de Seguins Pazzis It's the Hadamard product of the Hilbert matrix with itself, so it is positive definite and its determinant is positive.
Jul 10, 2013 at 17:40 comment added Todd Trimble I think this could stand some motivation.
Jul 10, 2013 at 17:38 history asked user36887 CC BY-SA 3.0