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Jul 9, 2013 at 4:29 comment added Benjamin Steinberg @Joel, more bad examples can be constructed by taking primitive permutation groups. See my addition.
Jul 9, 2013 at 4:27 history edited Benjamin Steinberg CC BY-SA 3.0
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Jul 9, 2013 at 3:50 history edited Benjamin Steinberg CC BY-SA 3.0
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Jul 9, 2013 at 3:47 comment added Joel David Hamkins Yes, that was the guiding idea of my example.
Jul 9, 2013 at 3:45 comment added Benjamin Steinberg @Joel, oops I read your example too quickly but it is the same issue. Each orbit of the group must have either the discrete or indiscrete topology. So you can crush 1 orbit and leave the other alone.
Jul 9, 2013 at 3:39 comment added Joel David Hamkins Thanks, Benjamin. But is my example really a special case of this? After all, my group of permutations is not transitive, and I had thought of that as a key reason why it worked.
Jul 9, 2013 at 3:37 history edited Benjamin Steinberg CC BY-SA 3.0
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Jul 9, 2013 at 3:31 history answered Benjamin Steinberg CC BY-SA 3.0