Timeline for Depth of ideals in a commutative ring
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 10, 2013 at 2:05 | comment | added | Pham Hung Quy | If your question has an affirmative amswer then $R/I^{(n)}$ is Cohen-Macaulay iff $R/I^{(n)}$ is Cohen-Macaulay for all $m, n$, where $I^{(n)}$ denotes the $n$th-symbolic power of $I$. This is not true in general (See arxiv.org/pdf/1003.2152.pdf). | |
| Jul 8, 2013 at 20:10 | comment | added | Andrei | Thanks, but what if we add, as I said above, the condition $I \subset J$ ? | |
| Jul 8, 2013 at 20:09 | vote | accept | Andrei | ||
| Jul 8, 2013 at 14:50 | history | answered | Pham Hung Quy | CC BY-SA 3.0 |