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Jul 8, 2013 at 9:00 comment added Derek Holt Although every finite subgroup of ${\rm GL}_n({\mathbb Q})$ is conjugate to a subgroup of ${\rm GL}_n({\mathbb Z})$, there are more conjugacy classes in the integral group than in the rational group, and it is considerably easier to compute them over the rationals, which is why they have to up to higher dimensions.
Jul 8, 2013 at 3:50 comment added v08ltu There is also "Finite Rational Matrix Groups" by Nebe and Plesken books.google.com.au/books?isbn=0821803433 And "Finite subgroups of GL_{24}(Q)" by Nebe. projecteuclid.org/euclid.em/1047915100 The wall is hit at 32, Nebe does 25 to 31 in "Finite subgroups of GL(n,Q) for 25 <= n <=31." Comm. Algebra 24 (7) (1996), 2341-2397. dx.doi.org/10.1080/00927879608825704
Jul 8, 2013 at 1:46 history answered Igor Rivin CC BY-SA 3.0