Timeline for Kaehler differentials on a nodal curve
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 8, 2013 at 14:06 | vote | accept | mkemeny | ||
| Jul 7, 2013 at 14:46 | comment | added | mkemeny | @PhilipEngel: My exact sequence should be in the correct order. $T_p$ is a subsheaf of $\Omega_p$, generated by the torsion form $tds$. See the discussion in the comments below. | |
| Jul 7, 2013 at 14:24 | comment | added | Philip Engel | I think everything is explained by the fact that your exact sequence is backwards. There is an exact sequence $0\rightarrow I_p\rightarrow \mathcal{O}\rightarrow T\rightarrow 0$ which when you tensor with $\Omega_C$ gives the result. | |
| Jul 7, 2013 at 9:10 | answer | added | user36560 | timeline score: 2 | |
| Jul 6, 2013 at 17:43 | comment | added | Alexander Chervov | You are right that Kaehler differential sheaf has torsion. I also do not understand their formula. What is ideal sheaf here? | |
| Jul 6, 2013 at 17:11 | history | edited | mkemeny | CC BY-SA 3.0 |
changed title to better reflect the question
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| Jul 6, 2013 at 17:10 | comment | added | mkemeny | Admittedly the title is unfortunately the same. But as far as I can tell the question is completely different! I want to know if the sheaf of Kaehler differentials is torsion free for an integral curve, and if the formula $\Omega_C \simeq \omega_c \otimes I_p$ is really true. The related question was about how to define the line bundle $\omega_C$. My question is perhaps more about the Kaehler differentials than the dualizing sheaf (and I have now changed the title!). | |
| Jul 6, 2013 at 12:22 | comment | added | IMeasy | hey you should check the related questions! look at this: mathoverflow.net/questions/58559/… | |
| Jul 6, 2013 at 11:01 | review | First posts | |||
| Jul 6, 2013 at 11:02 | |||||
| Jul 6, 2013 at 10:44 | history | asked | mkemeny | CC BY-SA 3.0 |