Timeline for Is an algebraic space over a DVR, whose special fibre and generic fibre are schemes, actually a scheme?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 24, 2013 at 8:50 | vote | accept | Heer | ||
| Jul 24, 2013 at 8:49 | vote | accept | Heer | ||
| Jul 24, 2013 at 8:50 | |||||
| Jul 24, 2013 at 8:49 | vote | accept | Heer | ||
| Jul 24, 2013 at 8:49 | |||||
| Jul 24, 2013 at 8:49 | vote | accept | Heer | ||
| Jul 24, 2013 at 8:49 | |||||
| Jul 5, 2013 at 12:21 | answer | added | Laurent Moret-Bailly | timeline score: 10 | |
| Jul 4, 2013 at 16:12 | comment | added | user61789 | Maybe it is implicit in your use of parentheses, but I'd like to just point out that the scheme property is inherited by the infinitesimal fibers without any hypotheses on the algebraic space. More generally, if $S$ is an algebraic space such that $S_{\rm{red}}$ is a scheme then $S$ is a scheme. (This is not so easy to prove when $S$ is not locally noetherian, but it is true.) | |
| Jul 4, 2013 at 14:13 | answer | added | Olivier Benoist | timeline score: 16 | |
| Jul 4, 2013 at 13:25 | comment | added | Heer | if this is true, could anyone please leave references? | |
| Jul 4, 2013 at 13:21 | history | asked | Heer | CC BY-SA 3.0 |