Timeline for Rank of normal closure of a subset
Current License: CC BY-SA 4.0
7 events
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| Apr 21, 2019 at 11:38 | history | edited | YCor | CC BY-SA 4.0 |
deleted 6 characters in body; edited tags; edited title
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| Jul 15, 2013 at 4:18 | comment | added | Zuriel | @NeilHoffman, Yes, $K_n$ is neither Abelian (unless $n=1$) nor the free group. In $K_n$, each generator $x_i$ commutes with all the conjugates of $x_n$. When $n=2$, it is the discrete Heisenberg group. | |
| Jul 10, 2013 at 20:47 | comment | added | Neil Hoffman | As stated the rank of the normal closure of $\{ x_n \}$ in $K_n$ could be 1 if $K_n$ is abelian and infinite if $K_n$ is the free group. Do you also mean that $x_i$ only commutes with elements it is conjugate to? | |
| Jul 4, 2013 at 11:16 | comment | added | Zuriel | Yes, they are exactly the same. | |
| Jul 4, 2013 at 8:58 | comment | added | Nick Gill | Is conjugate closure the same as normal closure? | |
| Jul 3, 2013 at 3:28 | history | edited | Zuriel | CC BY-SA 3.0 |
correction to a typo
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| Jul 3, 2013 at 3:11 | history | asked | Zuriel | CC BY-SA 3.0 |