Timeline for Embedding of the product of two Grassmannians into a Grassmannian
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
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S Jul 30, 2013 at 19:41 | history | suggested | Daniele Zuddas |
I think that differential-topology is an appropriate tag
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Jul 30, 2013 at 19:10 | review | Suggested edits | |||
S Jul 30, 2013 at 19:41 | |||||
Jul 2, 2013 at 9:57 | comment | added | user81500 | Thank you for your answer. I am thinking about smooth embeddings...... | |
Jul 1, 2013 at 19:13 | comment | added | Serge Lvovski | @Neil. The algebraic version is pretty easy: if dimension of the ambient Grassmannian is at least four, then no such embedding exists. Indeed, Picard group of any Grassmannian is $\mathbb Z$, so each divisor is ample, so Picard of each codimension one smooth subvariety is also $\mathbb Z$. | |
Jul 1, 2013 at 17:29 | comment | added | Neil Strickland | Are you thinking about algebraic embeddings (as suggested by quid's tags) or about smooth or topological embeddings? I suspect that all three versions are quite hard, but the algebraic version should be easier than the other two. | |
Jul 1, 2013 at 17:24 | comment | added | user9072 | Welcome to MO! I added the tag ag.algebraic-geometry; it is costumary to always use at least one of the top-level tags, those with a two-letter prefix corresponding to arXiv categeroies. I hope I picked the right one, you can always change this via using the link edit below the question. | |
Jul 1, 2013 at 17:22 | history | edited | user9072 |
tag
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Jul 1, 2013 at 16:51 | review | First posts | |||
Jul 1, 2013 at 17:24 | |||||
Jul 1, 2013 at 16:33 | history | asked | user81500 | CC BY-SA 3.0 |