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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jul 1, 2013 at 13:14 comment added Zhi Qi Thanks. I really have learned. I learned PDE by Evans' book with the conventional $D f = \nabla f$, so I did not realize the difference. I am a number and representation theorist. Bessel functions comes in naturally in my field, and I am trying to understand it via stationary phase method. That is why I encountered this "inconsistency".
Jul 1, 2013 at 13:03 vote accept Zhi Qi
Jul 1, 2013 at 13:00 comment added Willie Wong @ZhiQi As a side remark: in literature concerning harmonic/fourier analysis (including pseudo/para differential calculus), the normalisation $D = -i \partial$ is very common, as it has the advantage $\widehat{Df} = \xi \widehat{f}$ which is somewhat more convenient when you do algebraic manipulations of the symbol.
Jul 1, 2013 at 12:50 vote accept Zhi Qi
Jul 1, 2013 at 13:03
Jul 1, 2013 at 12:48 comment added Zhi Qi Thanks very much. I need this result for my research, but I am not an expect in analysis, so I took the conventional D for granted.
Jul 1, 2013 at 11:59 history answered Willie Wong CC BY-SA 3.0