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Jul 4, 2013 at 3:39 vote accept ccire
Jul 1, 2013 at 11:52 comment added v08ltu The point is, in the Intro they were dealing with a function $f$ that was not finitely supported, so $\Delta$ had the $x$-cutoff in it, to make it easier to talk about. When they introduce the convolution of Motohashi, then the sequence $\alpha\star\beta$ is already finitely supported (though in a way that depends on $x$), so the prior convention is not any longer in value.
Jul 1, 2013 at 9:59 comment added ccire I don't know, but if this is the case, then the $n$-restriction on $\Delta$ in this example would be in $(x,4x]$, which seems quite unusual.
Jul 1, 2013 at 9:43 history answered v08ltu CC BY-SA 3.0